Question 956569
It's a multiple of {{{ 4 }}} , so I can call
it {{{ 4n }}} where {{{ n <= 12 }}}
If {{{ n = 13 }}}, then {{{ 4*13 = 52 }}}
which is too much
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I am told:
{{{ ( 4n + 4 ) / 5 }}} is a whole number
Call the whole number {{{ k }}}
{{{ 4*( n + 1 ) / 5 = k }}} 
{{{ n + 1 = ( 5/4 )*k }}}
{{{ n = (5/4)*k - 1 }}}
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From above, I can say:
{{{ (5/4)*k - 1 <=12 }}}
{{{ (5/4)*k <= 13 }}}
{{{ k <= (4/5)*13 }}}
{{{ k <= 52/5 }}}
{{{ k <= 10 }}}
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{{{ k = 8 }}} gives me a whole number for {{{ n }}}
{{{ n = (5/4)*k - 1 }}}
{{{ n = (5/4)*8 - 1 }}}
{{{ n = 9 }}}
{{{ 4n = 36 }}}
The number is 36
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check:
{{{ 36/4 = 9 }}}
OK
{{{ ( 36 + 4 ) / 5 = 40/5 }}}
{{{ 40/5 = 8 }}}
OK