Question 956426
a train 100 meter long completely passes a man walking in the same direction at 2km/h in 9seconds.
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Find the speed in the relation to the man in meters/sec
100/9 = 1l.11 m/sec
In km/h: {{{((3600*11.11))/1000}}} = 40 km/h in relation to the man
Who is walking at 2 km/h, therefore Actual train speed is 42 km/h
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 and a car traveling in opposite direction in 3 second at what speed was the car traveling?
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Find the speed in relation to the car: 
100/3 = 33.3 m/sec
In km/h: {{{((3600*33.33))/1000}}} = 120 km/hr
Since the train (42 km/hr) and car (s) are going in the opposite direction, their relative speed is the sum of the car speed and the train speed
s + 42 = 120
s = 120 - 42
s = 78 km/hr is the actual speed of the car 
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Did this seem to make sense to you?? ankor@att.net