Question 956370
 A cylindrical tank 2.44m in diameter and 4.88m high is filled with oil.
 Another tank is to be built which will be sufficient to hold the oil in the first tank.
 How high must be the second tank if its diameter is twice that of the first?
:
We use the formula for the volume of cylinder: {{{V = pi*r^2*h}}}
let h = height of the 2nd tank
:
1st tank vol = 2nd tank vol(radius is doubled)
{{{pi*r^2*4.88}}} = {{{pi*(2r)^2*h}}}
{{{pi*r^2*4.88}}} = {{{pi*4*r^2*h}}}
divide both sides by {{{pi*r^2}}}
4.88 = 4h
h = 4.88/4
h = 1.22 m