<PRE><B>Question 956212</B>
 On the first part of a road trip to Batangas travelling on the highway, Kelly averages 60 kph.
 On the rest of the roadtrip, which was 10 kilometers longer than the first part, she averaged 50 kph.
 Find the total distance to Batangas if the second part of the trip took 30 minutes more than the first.
:
let d = distanced traveled the first part of the trip at 60 kph
then
(d+10) = distance traveled the second part at 50 kph, (10 km longer)
:
Change 30 min to 1/2 hr
:
Write a time equation; time = dist/speed
:
50kph time - 60kph time = 1/2 hr
{{{((d+10))/50}}} - {{{d/60}}} = {{{1/2}}}
multiply by 300 to cancel the denominators, then you have:
6(d+10) - 5d = 150
6d + 60 - 5d = 150
6d - 5d = 150 - 60
d = 90 km is the 1st part of the trip
then
90 + 10 = 100 km is the 2nd part
and
90 + 100 = 190 km is the total distance to Batangas. Philippines?
:
:
Confirm this, find the actual time of each part of the trip
100/50 = 2 hrs
90/60 = 1.5 hrs
----------------
time dif: .5 hrs</PRE>