Question 81606
10/(y-8) - 1/(x+1)
=[10(x+1)-(y-8)]/[(y-8)(x+1)]
=[10y+10-y+8]/[(y-8)(x+1)]
=[9y+18]/[(y-8)(x+1)]
=[9(y+2)]/[(y-8)(x+1)]
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Cheers,
Stan H.