Question 81605
loga[(x^2y^-3)^4/(xy)]
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Comment: All of this is log (base a) but I'm not repeating it.
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log[(x^8y^-12/(xy)]
= 8logx -12logy -log(xy)
=8logx -logy -logx - logy
= 7logx -2logy
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Cheers,
Stan H.