Question 956326

{{{log(10, (2.5 ))=log(10,(5/2))=log(10,(5))-log(10,(2))=log(5)/log(10)-log(2)/log(10)=0.69897-0.301029995663981=0.39794}}}

and 
{{{log(10,(1.5))=log(10,(3/2))=log(10,(3))-log(10,(2))=log(3)/log(10)-log(2)/log(10)=0.47712125472-0.301029995663981=0.1760913}}}