Question 956286
The length of one rectangular field is 400m more that the side of a square fields. The width is 100 m more than the side of the square field. If the rectangular field has twice the area square field, what the dimensions of each field?
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let x=side of  the square field
x+400=length of rectangular field
x+100=width of rectangular field
(x+400)(x+100)=2x^2
x^2+500x+40000=2x^2
x^2-500x-40000=0
solve for x by quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a=1, b=-500, c=-40000
ans:
x≈570.156
x+400=970.156
x+100=670.156
side of  the square field≈570 m
length of rectangular field≈970 m
width of rectangular field≈670 m