Question 956157
The height of the pyramid is 14ft-9ft=5ft
Half the length of the 20 ft side is one leg to find the slant height of the 30 ft side, the other leg is the height.
{{{sqrt(10^ft^2+5^2ft^2)=sqrt(125ft^2)}}}=slant height 30ft side
The two triangles that form the roof on the two 30 ft sides have area
{{{2(1/2)(30ft)sqrt(125ft^2)=30(sqrt(125ft^2))}}}={{{335.410ft^2}}}
Half the length of the 30 ft side is one leg to find the slant height of the 20 ft side, the other leg is the height.
{{{sqrt(15^2ft^2+5^2ft^2)=sqrt(250ft^2))}}}=slant height 20ft side.
The two triangles that form the roof on the two 20 ft sides have area 
{{{2(1/2)(20ft)sqrt(250ft^2)=20(sqrt(250ft^2))}}}={{{316.228ft^2}}}
Total area of the roof=335.410 sq ft+316.228 sq ft=651.638 sq ft.