Question 956135
A=number of adult tickets; C=number of child tickets
A+C=60
A=60-C
$11A+$6C=$460 Substitute for A
$11(60-C)+$6C=$460
$660-$11C+$6c=$460 Subtract $660 from each side.
-$5C=-$200 Divide each side by -$5
C=40 ANSWER 1: There were 40 children's tickets sold.
A=60-C=60-40=20 ANSWER 2: 20 adult tickets were sold.
CHECK:
$11A+$6C=$460
$11(20)+$6(40)=$460
$220+$240=$460
$460=$460
I was asked to do this using x and y as variables:
A=x; C=y
x=number of adult tickets; y=number of child tickets
x+y=60
x=60-y
$11x+$6y=$460 Substitute for x
$11(60-y)+$6y=$460
$660-$11y+$6y=$460 Subtract $660 from each side.
-$5y=-$200 Divide each side by -$5
y=40 ANSWER 1: There were 40 children's tickets sold.
x=60-y=60-40=20 ANSWER 2: 20 adult tickets were sold.
CHECK:
$11x+$6y=$460
$11(20)+$6(40)=$460
$220+$240=$460
$460=$460