Question 956142
a=short side; b=middle side=a+5in; c=long side=hypotenuse=a+10in
{{{a^2+b^2=c^2}}}
{{{a^2+(a+5in)^2=(a+10in)^2}}}
{{{a^2+a^2+10a+25=a^2+20a+100}}}
{{{a^2-10a-75=0}}}*[invoke quadratic "a", 1, -10, -75 ]
a=15 ANSWER 1: The shortest side is 15 inches.
b=a+5in=15in+5in=20in ANSWER 2: The middle side is 20 inches long.
c=a+10in=15in+10in=25in ANSWER 3: The hypotenuse is 25 inches.
CHECK:
{{{a^2+b^2=c^2}}}
{{{15^2in^2+20^2in^2=25^2in^2}}}
{{{225in^2+400in^2=625in^2}}}
{{{625in^2=625in^2}}}