Question 955877
Let {{{ n }}} = the smaller number 
{{{ n + 6 }}} = the larger number
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given:
{{{ n*( n + 6 ) = 27 }}}
{{{ n^2 + 6n - 27 = 0 }}}
{{{ ( n + 9 )*( n - 3 ) = 0 }}}
{{{ n = 3 }}}
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{{{ n+6 = 9 }}}
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The numbers are 3 and 9
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also, the other solution is:
{{{ n = -9 }}}
{{{ n + 6 = -3 }}}
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The numbers are -3 and -9
also