<PRE><B>Question 955829</B>
A ship left port A with a speed of 40 mph. In 1 hour and 15 minutes, a second ship left the port with a speed of 60 mph. In how many hours and at what distance from port A will the second ship catch up with the first one?
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1st ship DATA:
rate = 40 mph ; time = x hrs ; distance = 40x miles
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2nd ship DATA:
rate = 60 mph ; time = (x-(5/4)) hrs ; distance = 60(x-(5/4)) miles
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Equation::
dist = dist
40x = 60x - 75
20x = 75
x = 15/4 hrs
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Dist from 1st port:: 40x = 40(15/4)  = 150 miles
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Cheers,
Stan H.</PRE>