Question 955814
If sin theta=3/10,theta in quadrant II,find the exact value of 
(a)cos theta
{{{cos^2(t) + sin^2(t) = 1}}} for all angles
--> {{{cos(t) = sqrt(1 - sin^2(t))}}}
cosine is negative in Q2
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 (b)sin(theta+pi/6)
sin(A+B) = sin(A)cos(B) + sin(B)cos(A)
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(c)cos(theta-pi/3)
Look up "half angle formulas" on Wikipedia.
It's explained in detail there.
  (d)tan(theta+pi/4)
tan = sin/cos
Look up "half angle formulas" on Wikipedia.
It's explained in detail there.