<PRE><B>Question 955677</B>
3 SQUARE ROOT OF 128(X^12)(Y^4)
-----
= 3sqrt(64*2*x^12*y^4)
-----
= 3*8*x^6*y^2*sqrt(2)
---------
= 24x^6*y^2*sqrt(2)
============
Cheers,
Stan H.
-----------</PRE>