Question 955618
 a six foot high,conical wall tank is filled to the top.
When a valve at the bottom of the tank is open, the height h, in feet of the water in the tank is given by
 h = (88.18-3.18t)^2/5 where t is the time in seconds after the valve is opened. Round answer to the nearest tenth find the height of water 14 seconds after the valve is opened.
h = (88.18-(3.18*14))^2/5 
h = (88.18 - 44.52)^(2/5)
h = 43.66^(2/5)
h = 4.5 ft
:
 how long will it take to empty the tank?
h=0
(88.18-(3.18t))^2/5 = 0
We want the value inside the brackets to = 0; when this happens, we can ignore the exponent
88.18 - 3.18t = 0
-3.18t = -88.18
3.18t = 88.18
t = 88.18/3.18
t = 27.7 sec to empty the tank