<PRE><B>Question 81527</B>

Let the price of tape recorder = $x  and price of radio = $y

we have    5x + 7y = 823    --- (1)
and        5x -7y = 137     --- (2)


adding both equations we get

10x = 823-137 = 960
x = 960/10 = 96

putting this value of x in (1)
5(96) + 7y = 823
480 + 7y = 823
7y = 823-480 = 343
y = 343/7 = 49

therefore cost of taperecorder is $96  and of radio is $49

Hope the solution is clear to you. If you have any doubt, you can contact me on jainenderkapoor@gmail.com  I am also available for online tutoring at very reasonable rates.

Jainender Kapoor
</PRE>