Question 955277
W=width; L=length=W+5m
A=L*W Substitute for L.
{{{22m^2=(W+5m)W}}}
{{{22m^2=W^2+5Wm}}} Subtract 22m^2 from each side.
{{{0=W^2+5Wm-22m^2}}}*[invoke quadratic "W", 1, 5, -22 ]
W=2.815m ANSWER 1: The width is 2.815 meters.
L=7.815m ANSWER 2: The length is 7.815 meters.
CHECK:
A=L*W
{{{22m^2=(7.815m)(2.815m)}}}
{{{22m^2=21.999m^2}}}