Question 81501
{{{log(5,54)}}}
{{{log(5,2*27)}}}
{{{log(5,2*3^3) }}}
{{{log(5,2)+log(5,3^3) }}}
{{{log(5,2) + 3*log(5,3) }}}


Now, substitute in the values that are given:  {{{log(5,2)=.4307}}} and {{{log(5,3)=.6826 }}}


{{{log(5,2) + 3*log(5,3) }}}
{{{ .4307 + 3*.6826 }}}
{{{2.4785}}}


Of course, you can always check this answer by calculating 
{{{log(5,54) = (ln 54)/(ln5) }}}


The result is approximately the same!


R^2 at SCC