<PRE><B>Question 955374</B>
If the point (-8,-6) is on the terminal arm of angle A in standard position, then cos(A) is?
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cos(A) = x/r = -8/sqrt[8^2+6^2] = -8/sqrt(100) = -8/10 = -4/5
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Cheers,
Stan H.
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 a. -4/5
 b. -3/5
 c. 3/5
 d. 4/5 
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