Question 955359
1) OK
2) Yes, correct
3) Slope in this problem means it the change in population per year so the population was increase at roughly 2.3 million people per year since 1920.
4) You use two data points to solve for the two unknowns,
1920  -> 0-106
2000  -> 80-281.4
{{{A=A[0]e^(kx)}}}
So when {{{t=0}}}, {{{A=106}}}
{{{106=A[0]e^(0)}}}
{{{A[0]=106}}}
and
when {{{x=80}}}, {{{A=281.4}}}
{{{281.4=106e^(80x)}}}
{{{e^(80t)=2.654717}}}
{{{80k=ln(2.654717)}}}
{{{k=ln(2.654717)/80}}}
{{{k=0.0122}}}
.
.
{{{y=106e^(0.0122x)}}}
.
.
5) I get a slightly different answer using an online regression calculator 
{{{y=107.4367(1.0121)^x}}}
6) Yes, that's correct, take your multiplier, subtract 1 and multiply by 100 to get the annual percentage growth rate.