Question 955362
Angle CEB and angle AEB lie on line AEC and since angle CEB=55 degrees, AEB=125 degrees. FBE and CBE are supplementary along line FBC.Angle FBE=angle FBA (90 degrees)+ angle ABE (25 degrees)=115 degrees, so angle CBE=65 degrees. Angle ADE is alternate to angle CBE, so angle ADE=65 degrees. In triangle ABE we have angle ABE=25 degrees, Angle AEB=125 degrees, so angle EAB=180-125-25=30 degrees
ANSWERS: ANGLE ADE=65 degrees and angle EAB=30 degrees.