Question 955363
a=first number; b=second number=3a+2; c=third number=2b+3=2(3a+2)+3=6a+7
a+b+c=79 Substitute for b and c.
a+3a+2+6a+7=79
10a+9=79
10a=70
a=7 ANSWER 1: The first number is 7.
b=3a+2=3(7)+2=21+2=23 ANSWER 2: The second answer is 23.
c=2b+3=2(23)+3=46+3=49 ANSWER 3: The third number is 49.
CHECK:
a+b+c=79
7+23+49=79
79=79