Question 955354

{{{log(2,(3))}}} or {{{log(3,(8))}}}.......change the base

{{{log((3))/log(2)}}} or {{{log((8))/log(3)}}}

{{{log((3))/log(2)}}} or {{{log((2^3))/log(3)}}}

{{{log((3))/log(2)}}} or {{{3log((2))/log(3)}}}

so,
{{{log(3,(8))>log(2,(3))}}}