Question 955301
{{{8y^2 - 2x^2 -32y -16x -32 = 0}}}
{{{(8y^2-32y)-(2x^2+16x)-32=0}}}
{{{8(y^2-4y) - 2(x^2+8x) -32 = 0}}}
{{{8(y^2-4y+4) - 2(x^2+8x16) -32 = 8(4)-2(16)}}}
{{{8(y-2)^2 - 2(x+4)^2 = 32-32+32}}}
{{{8(y-2)^2 - 2(x+4)^2 = 32}}}
{{{(y-2)^2/4 - (x+4)^2/16 = 1}}}