Question 81521
Given that the distance is directly proportional to to the square of velocity.
Let 'd' be the distance and 'v' be the velocity.
Then d = K v^2 where K is the constant of proportionality
==>  112.5 = K (15)^2
==>  112.5 = K * 225
==>   112.5/225 = K
==>   K = 0.5

Case(ii)

Given v = 25

So d = K*v^2
     = 0.5 * (25)^2

     = 0.5 * 625

    = 312.5

So 312.5 meters are needed to stop at 25 Km/hr