Question 955145
Using the vertex form,
{{{y=a(x-1)^2+2}}}
Then using the point,
{{{-6=a(-1-1)^2+2}}}
{{{a(-2)^2=-8}}}
{{{a(4)=-8}}}
{{{a=-2}}}
So then,
{{{highlight(y=-2(x-1)^2+2)}}}
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{{{drawing(300,300,-8,8,-12,4,grid(1),circle(1,2,0.3),circle(-1,-6,0.3),graph(300,300,-8,8,-12,4,-2(x-1)^2+2))}}}