Question 955124
{{{ax+by=1}}}
When {{{x=0}}},{{{y=-1}}}
{{{b(-1)=1}}}
{{{b=-1}}}
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When {{{y=0}}},{{{x=1}}}
{{{a(1)=1}}}
{{{a=1}}}
So then,
{{{x-y=1}}}
{{{y=x-1}}}
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{{{m=1}}}
{{{b=-1}}}
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{{{drawing(300,300,-5,5,-5,5,grid(1),circle(0,-1,0.2),circle(1,0,0.2),graph(300,300,-5,5,-5,5,x-1))}}}