Question 81433

I believe that the question is

(15 + sqrt(54) )/3
let us first solve the numerator

15 + sqrt(54)
3x5 + sqrt(3x3x3x2)       (writing the factors of 15 = 3x5  and 54 = 3x3x3x2)
3x5 + 3sqrt(3x2)          (from one pair 3x3 one 3 can be taken out of sqrt)
3(5 + sqrt(6))            (taking out 3 common from both the terms)

3(5 + sqrt(6)) / 3        We have denominator as 3

(5 + sqrt(6))            is the final answer.


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