Question 955043
What is the area of an equilateral triangle whose perimeter is 28 in?
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For any regular polygon with n sides of length s:
{{{Area = ns^2*cot(180/n)/4}}}
= {{{3*(28/3)^2*sqrt(3)/12}}}
{{{(28/3)^2*sqrt(3)/4}}}
= {{{196*sqrt(3)/9}}}
=~ 37.72 sq inches