Question 955043
You can calculate the height of the triangle,
{{{S^2=(S/2)^2+H^2}}}
{{{(28/3)^2=((1/2)(28/3))^2+H^2}}}
{{{H^2=(28^2-28^2/4)/3^2}}}
{{{H^2=(3/4)(28/3)^2}}}
{{{H=(sqrt(3)/2)(28/3)}}}
So then the area is,
{{{A=(1/2)(28/3)(sqrt(3)/2)(28/3)}}}
{{{A=(196/9)sqrt(3)}}}{{{in^2}}}