Question 955045
Let the consecutive integers be:
{{{ n }}}, {{{ n+1 }}}, {{{ n +2 }}}, and {{{ n+3 }}}
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given:
{{{ n + n + 1 + n + 2 + n + 3 = 154 }}}
{{{ 4n + 6 = 154 }}}
{{{ 4n = 148 }}}
{{{ n = 37 }}}
{{{ n + 1 = 38 }}}
{{{ n + 2 = 39 }}}
{{{ n + 3 = 40 }}}
The 3rd number is 39
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check:
{{{ 37 + 38 + 39 + 40 = 154 }}}
{{{ 154 = 154 }}}
OK