Question 954920
I need help with this trig problem: 
If sec(2x+8) = csc(5x-2) , find the value of x.
1/cos(2x+8)=1/sin(5x-2)
cos(2x+8)=sin(5x-2)
Identity: cos(90-x)=sinx, that is, 90-x+x=90
2x+8+5x-2=90
7x=84
x=12