Question 954964
x and y are integers
x-y=3
x=y+3
xy=40 Substitute for x
{{{(y+3)y=40}}}
{{{y^2+3y=40}}} Subtract 40 from each side.
{{{y^2+3y-40=0}}}*[invoke quadratic "y", 1, 3, -40 ]
y=5 ANSWER 1: One of the integers is 5.
x=y+3=5+3=8 ANSWER 2: The other integer is 8.
CHECK:
xy=40
(8)(5)=40
40=40