Question 954876
t number of years, {{{11211*(1.0418)^t=96627}}}


Whichever base you want.


{{{1.0418^t=96627/11211}}}


{{{t*log(10,1.0418)=log(10,96627)-log(10,11211)}}}


{{{highlight_green(t=(log(10,((96627)/(11211)))/log(10,(1.0418))))}}}