Question 954914
{{{d[1]}}}= one diagonal; {{{d[2]}}}= the other diagonal; {{{A=(d[1]d[2])/2}}}
{{{(d*(2d+3))/2=50in^2}}}
{{{(2d^2+3d)/2=50in^2}}} Subtract 50in^2 from each side.
{{{d^2+1.5d-50in^2=0}}}*[invoke quadratic "x", 1, 1.5, -50 ]
d=6.36 ANSWER: One of the diagonals is 6.36 inches
2d+3=2(6.36)+3=12.72+3=15.72 in ANSWER 2: The other diagonal is 15.8 inches
CHECK:
{{{(d[1]*d[2])/2=Area}}}
{{{(6.36in*15.72in)/2=50in^2}}}
{{{99.98in^2/2=50in^2}}}
{{{50in^2=50in^2}}}