Question 81489

2x + 3y = 1      ---- (1)

5x + 3y = 16     ---- (2)

Subracting (1) from (2) we get

5x + 3y - 2x - 3y = 16 - 1
5x - 2x + 3y - 3y = 16 - 1
3x = 15
3x/3 = 15/3         (Dividing both sides by 3)
x = 5

Putting this value of x in (1) we get

2(5) + 3y = 1
10 + 3y = 1
10 +3y - 10 = 1-10        (Subtracting 10 from both sides)
3y = -9
3y/3 = -9/3           (Dividing both sides by 3)
y = -3

So the unique solution is (5, -3)

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