Question 954277
let x = the cost of a pizza
let y = the cost of a hockey ticket
We can now substitute the {{{x}}} and {{{y}}} in for the pizza and hockey tickets:
{{{2x+4y=210}}} and
{{{4x+10y=516}}}
Of course, there are 3 different ways to solve systems of linear equations. They are graphing substitution, and elimination. For this system, I will use elimination.
We first multiply the first equation by 2 get both {{{x}}}'s with the same coefficient:
{{{4x+8y=420}}}
{{{4x+10y=516}}}
Now that we both equations, we can subtract them from each other to eliminate the {{{x}}}. Subtracting the second equation from the first equation gives us 
{{{2y=94}}}
Divide by 2 and then we get
{{{y=47}}
So a hockey ticket costs $47
Now we can just plug the {{{y}}} back into the original first equation to get:
{{{2x+4(47)=210}}}
{{{2x+188=210}}}
{{{2x=22}}}
{{{x=11}}}
So a pizza costs $11.
A pizza costs $11 and a hockey ticket costs $47.