Question 954728
A({{{-5}}}, {{{0}}}), 
B({{{-2}}}, {{{0}}}), 

C({{{0}}},{{{ -3}}}), 
D({{{0}}},{{{ -y}}}),


distance {{{OA=5 }}}units left 
distance {{{OB= 2}}}units left 
distance {{{OC= 3}}}units down
distance {{{OD= y}}} units down

distance {{{OA/OB= OC/OD}}} => {{{5/2=3/y}}} => {{{5y=6}}}=>{{{ y=1.2}}} units  down, means {{{y}}} coordinate is {{{-1.2}}}

or this way:
{{{-5/-2=-3/y}}}
{{{-5y=-3(-2)
{{{-5y=6}}}
{{{y=6/-5}}}
{{{y=-1.2}}}

so, answer is: D({{{0}}}, {{{-1.2}}})


 {{{drawing( 600, 600, -10, 10, -10, 10, 
circle(-5,0,.12), circle(-2,0,.12),
circle(0,-1.2,.12),circle(0,-3,.12),
locate(-5,0.5,A(-5,0)),locate(-2,0.5,B(-2,0)),
locate(0.3,-3,C(0,-3)),locate(0.3,-1.2,D(0,-1.2)),
line(-5,0,0,-3),line(-2,0,0,-1.2),
graph( 600, 600, -10, 10, -10, 10, 0)) }}}