Question 954533
s=square; t=triangle
1s+4t=141cm^2
s=141cm^2-4t
2s+2t=192cm^2 Substitute for s.
2(141cm^2-4t)+2t=192cm^2
282cm^2-8t+2t=192cm^2 Subtract 192cm^2 from each side.
90cm^2-6t=0 Add 6t to each side.
90cm^2=6t Divide each side by 6.
15cm^2=t ANSWER 1; The area of the triangles is 15 square centimeters.
s=141cm^2-4t
s=141cm^2-4(15cm^2)
s=141cm^2-60cm^2
s=81cm^2 ANSWER 2: The area of each square is 81 square centimeters.
CHECK:
2s+2t=192cm^2
2(81cm^2)+2(15cm^2)=192cm^2
162cm^2+30cm^2=192cm^2
192cm^2=192cm^2