<PRE><B>Question 954484</B>
A toy rocket is launched from the top of a building 340 feet tall at an initial velocity of 80 feet per second. The height of the rocket t seconds after launch is given by the equation s(t)=-16t^2+80t+340. When does the rocket reach its maximum height? What is the maximum height?
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Maximum height occurs when t = -b/2a
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t = -80/(2*-16) = 2.5 seconds
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Max height = s(2.5) = -16(2.5)^2 + 80(2.5) + 340 = 442.5 ft
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Cheers,
Stan H.
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