Question 81363
*[invoke quadratic_factoring 1, 0, -16]


You can also use the difference of squares by noticing that {{{x^2-16}}} is in the form {{{a^2-b^2}}} where a=x and b=4 so following the difference of squares we get


Difference of squares
{{{a^2-b^2=(a+b)(a-b)}}}


Plug in a=x and b=4


{{{x^2-4^2=(x+4)(x-4)}}}


which is what we got orginally