Question 954432

The perimeter of a triangle is:{{{P=a+b+c}}}

given:
 {{{P=13in}}}
side {{{a}}}
side {{{b=2a}}}
side {{{c=a+1in}}}

substitute given values in {{{P=a+b+c}}}

{{{13in=a+2a+(a+1in)}}}..............solve for {{{a}}}

{{{13in=4a+1in}}}

{{{13in-1in=4a}}}

{{{12in=4a}}}

{{{12in/4=a}}}

{{{highlight(a=3in)}}}

now find other two sides:


side {{{b=2a}}}=>{{{highlight(b=6in)}}}
side {{{c=a+1in}}}=> {{{highlight(c=4in)}}}