Question 954398

given: 
a rectangle with a length {{{L}}} and a width {{{W}}}
given that a rectangle has a length {{{L}}} that is five times longer than its width {{{W}}}
=> {{{L=5W}}}

given that the perimeter of the rectangle is {{{P=12in}}},   and you know that {{{P=2L+2W}}}
 
so,{{{2L+2W=12in}}}

since given that  {{{L=5W}}},substitute it in {{{2L+2W=12in}}}

{{{2*5W+2W=12in}}}...........solve for {{{W}}}

{{{10W+2W=12in}}}

{{{12W=12in}}}

{{{W=12in/12}}}

{{{highlight(W=1in)}}}


so,the width is {{{highlight(1in)}}}

then the length is {{{highlight(5in)}}}


check perimeter:

{{{P=2*5in+2*1in}}}

{{{P=10in+2in}}}

{{{P=12in}}}