Question 954247
x*(x+1)*(x+2)-x^3= 33 Reorder terms
x*(1+x)*(2+x)-x^3= 33 Multiply as follows:
(1+x)*(2+x) = 2+1x+2x+x^2 So we now have:
x(2+1x+2x+x^2)- x^3= 33 Add on left:
x(2+3x+x^2)- x^3= 33 Multiply to eliminate parenthesis
2x+3x^2+x^3- x^3 = 33 Simplify, subtract on the left
2x+3x^2 = 33 Now, to get a quadratic equation, subtract 33 on both sides
2x+3x^2-33 = 0 Factor the equation:
(x-3)(3x+11) = 0 Solve each side separately:
x-3= 0; x= 3
3x+11= 0; 3x= -11; x= -11/3
Discard the negative. Let's try the other answer which is 3:
3*(3+1)*3+2)-3^3=
3*4*5-3^3
60-3^3= 60-27= 33 We got the right answer: 3