Question 954073
You didn't use a comma to separate your equations but I think this is your system,
{{{2x+2y=2}}}
{{{y=5-5x}}}
Substituting,
{{{2x+2(5-5x)=2}}}
{{{2x+10-10x=2}}}
{{{-8x=-8}}}
{{{x=1}}}
Then,
{{{y=5-5(1)}}}
{{{y=5-5}}}
{{{y=0}}}
(1,0)