Question 953993
Express commuter train #12 leaves the downtown station and travels at an average speed of 50miles per hour towards the north side station, which is 60 miles away.
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 Fifteen minutes later, express commuter train #7 leaves the north side station and travels at an average speed of 45miles per hour towards the downtown station.
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At the moment when the two trains pass each other, how far (in miles) is the #12 train from the downtown station and how long (in minutes) has the #12 train have been traveling?
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let t = travel time of #7 (in hrs, because we are dealing in mph))
then
(t+.25) = travel time of #12 (in hrs, left 15 min earlier)
:)
When the two trains meet, their total travel distances add up to 60 miles.
Write a distance equation, dist = speed * time
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#12 dist + #7 dist = 60 mi
50(t+.25) + 45t = 60
50t + 12.5 + 45t = 60
95t = 60 - 12.5
95t = 47.5
t = 47.5/95
t = .5 hrs, travel time of #7
then
.5 + .25 = .75 hrs is the travel time of #12
Find how far #12 has traveled in this time
.75*50 = 37.5 mi from the the downtown station
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"and how long (in minutes) has the #12 train have been traveling?"
convert to min: .75(60) = 45 min
:
;
Confirm this solution by finding the distance traveled by #7
.5*45 = 22.5 mi
Total distance should add up to 60
22.5 + 37.5 = 60 mi
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I have to commend you. 
The problem is written with Capital letters, punctuation, and correct spelling.
Unfortunately, you are the exception, not the rule around here.