Question 953991
The product of two consecutive integers is the square of the lesser integer minus 11.
 Find the greater of the two integers.
:
Two integers n, (n+1)
n(n+1) = n^2 - 11
n^2 + n = n^2 - 11
subtract n^2 fro both sides
n = -11 
then
-11 + 1 = -10 is the greater integer
:
see if that works
-11(-11 + 1) = (-11)^2 - 11
-11(-10) = 121 - 11
+110 = +110