Question 954041
     Let the present ages of son and his father are x and y respectively. 

   The difference of their ages is- (y-x).
 Hence, it will take (y-x) more years for son to reach his father's present age. After (y-x) years sum of their ages will be - (which is given 126)

.
.

    [  x + (y-x) ] + [ y + (y-x) ] = 126
.
.

    3y-x = 126.    ........  eq-1


Similarly (y-x)  before father's age was equal his son's present age. (y-x) years before sum of their age was- ( which is given 38)--

         [ x - (y-x) ] + [ y - (y-x) ] = 38
          
.
.
                   3x - y = 38.................  eq-2

          
   by multiplying eq-2 with 3 and then adding to the eq-1 

        3y - x  = 126
        9x - 3y = 114
    --------------------
        8x      = 240

          x = 30
Putting x =30 to the eq-2

          Y= 52

So son's age is 30 years and father's age is 52 years.