Question 954033

Given y=Px^2+Qx+R,find the values of P,A and R,when the roots x are -2 and 0 .5.
<pre>You must mean: P, Q, R since there's no "A" in the equation.

x = - 2
x + 2 = 0
Therefore, x + 2 is a factor of the trinomial

x = .5
x - .5 = 0 
2x – 1 = 0 ------- Multiplying by 2
Therefore, 2x - 1 is a factor of the trinomial

We now have: y = (x + 2)(2x – 1)
{{{y = 2x^2 + 3x - 2}}}
With {{{y = Px^2 + Qx + R}}}, it's lucid that: {{{highlight_green(system(P = 2,Q = 3_and,R = - 2))}}}